(x/x^2-25)-(x+3/x^2-5x)=(-7/x^2+5x)

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Solution for (x/x^2-25)-(x+3/x^2-5x)=(-7/x^2+5x) equation: 



(x/x^2-25)-(x+3/x^2-5x)=(-7/x^2+5x)

We move all terms to the left:

(x/x^2-25)-(x+3/x^2-5x)-((-7/x^2+5x))=0



Domain of the equation: x^2-25)!=0

x∈R





Domain of the equation: x^2-5x)!=0

x∈R





Domain of the equation: x^2+5x))!=0

x∈R



We get rid of parentheses

x/x^2-x-3/x^2+5x-((-7/x^2+5x))-25=0

We calculate fractions

We do not support expression: x^4

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